Will you gain more boost or horsepower is the intercooler temp was lowered? Say below zero. Scott

 

I would assume more boost but there is a catch. 8 PSI of 70* air contains more oxygen molecules than 8 PSI of 100* air so it could be misleading. I would bet the cooler denser air produces a higher boost rate than warmer air simply because the roots style is a positive displacement pump i.e. for every rotation of the screw X amount of air(for the sake of argument say 1 cubic foot) is compressed. One cubic foot of cooler air contains more molecules than warmer air so trying to force more air in is gonna create more resistance or pressure. My dollar two ninety-eights worth.

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The intercooler reduces the temperature of the compressed air, this will cause a loss of pressure. The more it cools the more pressure loss. Remeber that mods before the compressor (that work) will produce more boost, mods after the compressor(again, that work) will reduce boost.

[This message has been edited by 98_SVT_COBRA (edited 06-08-2000).]

 

4D has got it, the roots blower produces volumetric flow. The total quanity of air flow depends on the rotating speed of the blower. When ever a gas is compressed there is a corresponding increase in the temp. (Adiabatic heat of compression),at 8 lbs of boost the temp increase from inlet to outlet of the blower is fairly constant, regardless of the ambient air temp. Because the L has a stand alone intercooler/waste heat exchanger it will reduce the blower discharge air temp in direct relationship to the ambient air temp. In other words the boost pres. should not decrease any when the ambient air temp. gets cooler, this cooler denser air will just make your L product more HP.