Need help with some wiring
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Joined: Aug 2003
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From: Madison, FL
Need help with some wiring
OK, I have a 2003 f150 supercab 4.6 a/t. I have installed my laptop computer and a printer in my truck. I bought a 400W power inverter to run these items. But the instructions that come with the inverter says that I can only run up to 150W off of the cig lighter. I am wanting to wire the thing direct, but my truck has the 40 min. battery saver. Is there a way to wire this thing where the battery saver will still function if I leave it on by accident. If not I will just wire it directly to the Bat.
Thanks
Chuck
Thanks
Chuck
Technical Article Contributor
Joined: Jun 2002
Posts: 10,511
Likes: 10
From: Under the flightpath of old ORD 22R
Just an idea.
You can use a 30 or 40 amp relay, and power the coil of the relay with the battery saver circuit on the truck.
You need to check the draw on the 12 V side of the system to see what it is under load ( 400W of 110V AC ) to know for sure if it is a 30 or 40 amp relay.
The one quick place I see to get the battery saver circuit to run the coil on the relay is from the Central Junction box, the circuit that drives the glove box lamp and engine compartment lamp.
This is light green / orange wire in Connector C243 by the central junction box, or if you just want to put the relay under the hood ( as you are wiring the input to this to the battery direct with 12 / 14 AWG wire ) the power to the engine compartment lamp.
The power on both are the light green / orange stripe wire in both cases noted above. There are a few other places to get this circuit at, as well as if you would rather have these on the ACc delay relay that uses the battery saver circuit and shuts down the moment you open the door.
The Relay , the coil ( 85 ) is driven from the circuit (s) noted above, the other side of the coil (86) is ground. the input to the relay is a fused connection direct to the battery ( 30 ) and the output (87) is to the inverter. Needing the full load draw on teh 12 V side helps with relay sizing, fuse needs, and the size wire needed to run the inverter.
Let me know if this answers you question, or if you need a drawing to work from and which way you want to go with the power for it ( battery saver circuit alone, or the acc delay circuit that shuts down after the door is open ).
Good luck, let us know what happens next.
You can use a 30 or 40 amp relay, and power the coil of the relay with the battery saver circuit on the truck.
You need to check the draw on the 12 V side of the system to see what it is under load ( 400W of 110V AC ) to know for sure if it is a 30 or 40 amp relay.
The one quick place I see to get the battery saver circuit to run the coil on the relay is from the Central Junction box, the circuit that drives the glove box lamp and engine compartment lamp.
This is light green / orange wire in Connector C243 by the central junction box, or if you just want to put the relay under the hood ( as you are wiring the input to this to the battery direct with 12 / 14 AWG wire ) the power to the engine compartment lamp.
The power on both are the light green / orange stripe wire in both cases noted above. There are a few other places to get this circuit at, as well as if you would rather have these on the ACc delay relay that uses the battery saver circuit and shuts down the moment you open the door.
The Relay , the coil ( 85 ) is driven from the circuit (s) noted above, the other side of the coil (86) is ground. the input to the relay is a fused connection direct to the battery ( 30 ) and the output (87) is to the inverter. Needing the full load draw on teh 12 V side helps with relay sizing, fuse needs, and the size wire needed to run the inverter.
Let me know if this answers you question, or if you need a drawing to work from and which way you want to go with the power for it ( battery saver circuit alone, or the acc delay circuit that shuts down after the door is open ).
Good luck, let us know what happens next.