Ok, after talking to a audio head we kind of got in a little argument about power.

with a 1X600 PDX amp, running 2 subs at dual 2ohm voice coils, how much power is each sub getting.

Is it 600 or 300?

 

Depends. On whether it's putting out 600w @ 2 or 4 Ohms. Also, depends on whether you are wiring it in series or parallel. But if it's putting out 600w RMS x 1 @ 2 Ohms, and you have 2 subs wired in parallel to it, each sub is getting 300w RMS.

 

the PDX puts out the same power at 4 and a 2 ohms.

My subs are hooked up like this middle picture.
http://www.rockfordfosgate.com/rftec...2&woofer_imp=3

 

300 per sub, power is split up equally between however many subs there are

 

^^^Yup, what he said.

 

Hey! I said it first!

Also, it's only split up evenly if it's wired in parallel. But then again, most people don't wire it in series, so... yeah. At least, I THINK that's how it works...

 

Is there a way to wire it for more power?

 

The only way I know of involves wiring another amp or two in the loop.

 

Walked in to that one...

I will get another amp next year. I went out and messed with it tonight, I have to say I am pretty impressed with how it sounds...much better than what I had.

 

It will get the same in series too.

 

I thought in series, everything gets the same output voltage (like, output power = speaker power 1 = speaker power 2 = ...; whereas parallel output power = speaker power 1 + speaker power 2 + ...)? Ahh. I dunno. Maybe not with speakers. Who knows. Either way, you have your answer -- 300w.

 

Newp. Series or parallel, power is split up either way

 

This "audio-head" you spoke with.. Please tell me he does NOT work at an audio shop..

 

It is the same amount of current to each speaker in a series or parallel circuit, provided that all of the speakers are the same impedance. Normally the difference is the total amount of current, but the PDX amps have identical 2 Ohm and 4 Ohm specs so they must compensate internally for 2 Ohm loads. They won't give you any extra from bridging, either.

When wiring two speakers in series the impedance of each speaker is added together to come up with the load on the amp.

When wiring in parallel, (assuming both speakers are the same impedance) you divide the speaker impedance by the number of speakers.

(2) 4 Ohm speakers in parallel = 2 Ohm load
(2) 4 Ohm speakers in series = 8 Ohm load

The lower the load on the amp, the higher the current draw. (unless you're a PDX, apparently)

 

Hmm..
Not sure if you're trying to fully explain or just covering SVC drivers. But here's how it goes.
(2) DVC-4 Ohm speakers can equal either 1- or 4-Ohm Final Impediance
(2) SVC-4 Ohm speakers can equal either 2- or 8-Ohm Final Impediance