have lower intake manifold to install on 4.2L block. Haynes manual states torque specs as step 1 at 44 in lbs and step 2 at 89 in lbs. When converting these to foot lbs as my torque wrench is ft lbs I get 4 ft lbs and 8 ft lbs- is this right? Any help on these figures would be great!

 

To convert foot pounds to inch pounds, multiply by 12.
To convert inch pounds to foot pounds, divide by 12.



You might want to invest in a 3/8 drive w/inch lbs. - 1/2" Drives in foot lbs aren't that accurate when dialed down that far - unless you have a real nice one.

 

the conversion is not the problem, rounding up of course gave me the 2 step #'s. The idea of only torqueing the manifold to 8 ft lbs when thinking of what goes on in the manifold just does not seem right. Going to Ford today and ask, thanks for the tip, also you can x in lbs by .083 to get ft lbs.

 

I believe that it's a plastic manifold?

 

Yea, and sits on those special O-Ring type gaskets that can't have any contamination before install - "Like oil" - You Clean the head w/mineral spirits before install, any oil contamination will cause NEW gaskets to leak.

The light torque numbers - Reason ? You can't smash the gasket or it won't work. It's suppose to compress and sort of stick to a dry aluminum head. My intakes a little different, it's aluminum and has 3 tightening stages to compress instead of just the two. This doesn't require much torque to accomplish.

Hope that's the answer OP was looking for - If you want I'll pull the procedure from the service DVD and email to you if you know the year of yor motor.

 

[QUOTE=If you want I'll pull the procedure from the service DVD and email to you if you know the year of yor motor.[/QUOTE]

JBrew,
Sent you a PM on this. Can you help me please? Going to be putting my new intake gaskets on tomorrow.