Why does a KB heat the air more than an Eaton?
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From: Wilton, Ca.
Why does a KB heat the air more than an Eaton?
KB claims their blower lowers air temps as compared to an Eaton, and I would think it would also. The screw blower is much more efficient than the root style. Yet I'm hearing tuners claim the opposite (not all tuners though).
What's the real scoop? I'm talking psi being equal between the two, not 14 psi Eaton versus 24 psi KB. I would think the higher you go the Eaton would really fall behind in air temp, but even at street pressures the KB should be better.
Jody
What's the real scoop? I'm talking psi being equal between the two, not 14 psi Eaton versus 24 psi KB. I would think the higher you go the Eaton would really fall behind in air temp, but even at street pressures the KB should be better.
Jody
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From: Palm Coast, FL
Jody, I don't think it's a matter of the KB makes more heat than the Eaton, it's a matter of the KB is doing more work than the Eaton. The KB is 134 ci, vs the Eaton's 112. So right there the KB is compressing a higher volume of air, which equals more heat. Plus, and already mentioned, the twin screw compresses the incoming air differently than the roots does (between the screw rotors vs between the rotors and case) so that's more work as well, which also equals more heat. It DOES make more power, and it is more efficient, but you can't compare the two because of the displacement difference.
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A twin screw SC is always compressing air. No matter what the manifold pressure is, it is compressing the incoming air to the internal compression ratio. If the incoming air is at atmospheric pressure, the air is probably compressed internally to 14-16psi.
If the manifold pressure is below that internal compression ratio the air will expand, but the heat added during the compression is still there. So even though its more effiecent at compressing the air to 16psi, if you're manifold pressure is 14psi you're wasting it. This would be made even more apperant if you just spun them on a bench and measure the outlet temp... in that case the eaton would win by a landslide.
Thats the only thing I can think of that would make a twin screw less efficient.
If the manifold pressure is below that internal compression ratio the air will expand, but the heat added during the compression is still there. So even though its more effiecent at compressing the air to 16psi, if you're manifold pressure is 14psi you're wasting it. This would be made even more apperant if you just spun them on a bench and measure the outlet temp... in that case the eaton would win by a landslide.
Thats the only thing I can think of that would make a twin screw less efficient.