Where/What is the Mega Fuse?

Thank You!!!

 

12.1-12.5 volt out of the alt means it is on borrowed time. A new battery fully charged should be approx 12.5VDC, if you are getting 12.1VDC with the engine running you are discharging the battery slowly.

 

Megafuses -

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Sorry Last Splash but after your last few posts, your electrical opinion is null and void as you have NO clue what you are talking about

 

Um ok his alternator is fine and his battery is fine just keep on driving and dont worry about it. Evidently he has one of tham new batteries that is not made up of 6 individual cells with a 2.1VDC output and a sp gravity of 1.22@ 77F. And if you connect them is series you get 2.1VDC X 6 which comes out to 12.6VDC.
Not to sure maybe someone can help me here but if take a battery with 12.6VDC and connect it to a system and the battery voltage drops to 12.1VDC isnt that a discharge?

To get back to the power equation. If you have a 100W load and the voltage drops, unless you lower the system load there is still a 100W load. so looking at the equation P=I(amperes) X V(volts) If V lowers and P stays the same the current has to increase.
P1=I1xV1 P2=I2xV2 then if P1=P2 ---> I1xV1=I2xV2
I guess there is the proof I do not know what I am talking about. Not opinion.

 

Yoooour still out of wack with that explanation.
IF THE VOLTAGE DROPS, THERE IS NOT THE ELECTRICAL PRESSURE (voltage) THERE TO FORCE THE SAME POWER into the load!!!!!!
12 volts times 5 amps is 60 watts.
11 volts time a lesser amount of current being forced into the ((same load)) by the lower voltage = is less power.
How the hell do you figure it's more?

Where do you think the charging current comes from going back to the battery is it isn't the difference between the battery voltage and the regulator setting that controls alternator out put.
Again certainly less is not more.
Either you miss understand or don't really know.

 

What you are explaining is true for a purely resistive circuit, like a battery that powers only a light or heating element. The pcm in a vehicle is not a purely resistive load, a curcuit board requires a certain amount of power to operate and that power does not change. So back to the equation P=IxV. I have already explained that if P never changes and V lowers then I must increase. Try plugging in some numbers it works. But I will agree with you that in a purely resistive circuit if V drops so does I and subsequently so does the power consumed (P).
To explain it in simple terms. When the voltage drops your lights dim and the circuitry in your PCM heats up.

 

Man, you are nuts. bluegrass has got it dead on. ohms law applies to all electrical circuts, not just those that are merely resistive

 

Well, you just keep jumping from one thing to another.
This first started with the charge circuit now you at the PCM.
Making a statement that less is more is more is a stupid statement to make.
CHARGE SYSTEM ONLY:
How it works;
There are 3 major parts, the battery, alternator and it's system regulator.
The regulator has a built in reference set as 14.3 volts +/- any tolerence.
The reg. senses the battery voltage. When there is a diffeence in voltage at the battery, the regulator increases alt. output (voltage) forcing (higher) current into the battery.
As the voltage rises at the batt. the current tapes off, the forcing voltage drops, until the battery attains float.
After this point the alternator feed the rest of the truck directly.
The battery is there for two reasons. To start the motor and to be a sink and filter for the alternator and the reast of the truck..
If you analize this you will find as the voltage rises the current rises.
I could care less what happens anywhere else for purpose of this thread.
All charge/battery systems work the same no mater if a battery charger is used, solar power or generator; the principle is the same.
To bring up the number of cells and specific gravity is a show, when for this purpose, it's all fixed as part of the discussion (normal battery/normal alternator).!
Don't think for a moment I don't know all this, my friend. Spent more than 50 year at all this.
In my responses , I specificlly stated fixed loads (R) in response to this nonsense statement that less is more without any explanation of what your trying to say..
I fully understand that there are such things as negitive coefficient componants that lower resistance with voltage and tend to increase current until the supply voltge can no longer force current into the circuit then a reverse action occurrs as the total load resistance goes higher and become current limiting.
I'm done with this thread now.
Tell these people anything you like.