Stupid Question.
That's not correct. Make a chalk mark on the pavement at the particular point on the tire and payment where they intersect. Roll the truck back and make another mark where the tire contacts the pavement. That measurement will be different from the unloaded circumference. Trust me, I've programmed several PCM to get the speedometer correct. If I didn't have revolution per mile data (which essentially proves my point to begin with) I would take the measurement described above and see how may times that length went into a mile.
I also use that information to determine rpm at various speeds to determine final gear ratios. You guys don't have to believe me, but next time you're trying to program tire size changes in your programmers, remember this post when your speedometer is still off.
I also use that information to determine rpm at various speeds to determine final gear ratios. You guys don't have to believe me, but next time you're trying to program tire size changes in your programmers, remember this post when your speedometer is still off.
This isn't rocket science.
The calcs everyone has listed are easy ways to get in the ballpark of where your speedo will be, height and width when comparing two size tires. Once you decide on tires and size, if over or under sized a programmer will take care of the rest without all the math.
Let's agree to disagree...
Really, the only reliable data to use is the manufacturers revolutions per mile data to determine speedometer error. Published tire diameter is inaccurate information for that purpose. I'll just give an example. I have BFG Rugged Trail T/As on my truck. The revolution per mile data is 660, which is the same data programmed into the PCM to make calculations. If the tire turns 660 times in a mile, then it turns once every 96". Divide that by pi and you come up with 30.56" as the effective diameter. BFG claims the tire diameter is 31.9" and it probably is the diameter with no load. That difference is 4% alone. Consequently the metric sizing indicates it to be 32.1". Hope this helps.
Loaded or unloaded your splitting hairs, but if the tire is low on air the radius will change, and the revolutions will change along with the radius.
I think it's great that everyone is here and passes on information, I just simply disagree that the difference is that great and therefore can't make a difference. It's nothing personal, I just respectfully disagree. 
I know what you mean by loaded and Loaded is Loaded. The tire is loaded by the the truck and then by the payload...by your theory, they should both change the rolling circumference. You can't use one load and ignore the other. Both are minuscule to circumference so I don't buy it and that's ok.
I just think you're theory is bogus.
I never said anywhere I measured the tire OFF the truck. I take measurements for the Tirepaq while the tires are ON. This IS loaded with the truck weight and if I add a 1550lb load in the bed, by your theory, my speed will be off because I just loaded the tire more and changed it's circumference. I ain't buyin' it.
I never said anywhere I measured the tire OFF the truck. I take measurements for the Tirepaq while the tires are ON. This IS loaded with the truck weight and if I add a 1550lb load in the bed, by your theory, my speed will be off because I just loaded the tire more and changed it's circumference. I ain't buyin' it.
Last edited by TN-F150; Feb 28, 2009 at 10:15 AM.
This is my point exactly! Loaded is loaded no matter what the load is and none will change the tire enough to make a speedo off. Unless they are all flat then you would base it on the rim height and speed would not be an issue anyway. 
How much does your truck weigh!? Using Windsors theory, let's say your truck weighs 4000lb, divide by 4 and the average load on each tire is 1000lbs, now add 2000lbs to the bed and you just added another 1000lbs to each rear tire. Let's say for each 1000lbs the tire radius is reduced 1/4". If his theory is correct, the speedo is changed two fold. Not having any REAL numbers that could mean anything, but I have never seen my speedo off when hauling a load. How about wreckers, they haul half the weight of the vehicle behind them on just the rear tires. Will they get a ticket for speeding or going too slow? My point is, it would take a huge amount of ANY load to change the tire enough to throw off the speedo. It just isn't enough to change it.
Again, I agree to disagree...
Windsor's theory is the DEFINITION of splitting hairs.
sau4u, any of the calcs will get you in the ballpark and a tuner can adjust your speedo etc., so don't worry about being SO critical about this and that. There is no two speedo's that are exactly the same anyway but are within a range of acceptability. Ford and B.f. Goodrich are not designing and building Swiss watches here, with precise gears. There are variables and they know it.

How much does your truck weigh!? Using Windsors theory, let's say your truck weighs 4000lb, divide by 4 and the average load on each tire is 1000lbs, now add 2000lbs to the bed and you just added another 1000lbs to each rear tire. Let's say for each 1000lbs the tire radius is reduced 1/4". If his theory is correct, the speedo is changed two fold. Not having any REAL numbers that could mean anything, but I have never seen my speedo off when hauling a load. How about wreckers, they haul half the weight of the vehicle behind them on just the rear tires. Will they get a ticket for speeding or going too slow? My point is, it would take a huge amount of ANY load to change the tire enough to throw off the speedo. It just isn't enough to change it.
Again, I agree to disagree...
Loaded or unloaded your splitting hairs, but if the tire is low on air the radius will change, and the revolutions will change along with the radius.
sau4u, any of the calcs will get you in the ballpark and a tuner can adjust your speedo etc., so don't worry about being SO critical about this and that. There is no two speedo's that are exactly the same anyway but are within a range of acceptability. Ford and B.f. Goodrich are not designing and building Swiss watches here, with precise gears. There are variables and they know it.
It's never easy to communicate these concepts over the internet, but I think we're saying the same thing. Payload can alter the radius, but even a quarter inch of compression from an unloaded vehicle to a fully loaded vehicle only translates to a 1.5% difference. However, if you have a payload that is heavy enough to reduce the radius that much, it's a lot of weight and you probably should be airing up for that load anyway. That 1/4" would only translate to about a mile per hour difference at 70, and you'd never notice it. Most speedometers aren't that accurate anyway. The truth of the matter is the radius will change with speed to some degree as well, granted only slightly.
My point was that using the manufacturer's published diameter to program your speedometer will yield inaccurate results. The published tire revolutions per mile date, while not perfect, will yield better results. Ford uses revolution per mile data as a parameter in the PCM, ask any tuner worth his salt.
My point was that using the manufacturer's published diameter to program your speedometer will yield inaccurate results. The published tire revolutions per mile date, while not perfect, will yield better results. Ford uses revolution per mile data as a parameter in the PCM, ask any tuner worth his salt.

Payload can alter the radius, but even a quarter inch of compression from an unloaded vehicle to a fully loaded vehicle only translates to a 1.5% difference. However, if you have a payload that is heavy enough to reduce the radius that much, it's a lot of weight and you probably should be airing up for that load anyway. That 1/4" would only translate to about a mile per hour difference at 70, and you'd never notice it. Most speedometers aren't that accurate anyway. The truth of the matter is the radius will change with speed to some degree as well, granted only slightly.
My point was that using the manufacturer's published diameter to program your speedometer will yield inaccurate results. The published tire revolutions per mile date, while not perfect, will yield better results. Ford uses revolution per mile data as a parameter in the PCM, ask any tuner worth his salt.
Couple that with the fact I'm Cajun and can't use my hands to "s'plane tings lik dat" I lose half of my communication skills. We're using the same basic method, just different approaches to get the same end result.
Last edited by TN-F150; Feb 28, 2009 at 11:56 AM.
How much does your truck weigh!? Using Windsors theory, let's say your truck weighs 4000lb, divide by 4 and the average load on each tire is 1000lbs, now add 2000lbs to the bed and you just added another 1000lbs to each rear tire. Let's say for each 1000lbs the tire radius is reduced 1/4". If his theory is correct, the speedo is changed two fold. Not having any REAL numbers that could mean anything, but I have never seen my speedo off when hauling a load.
I know what you mean by loaded and Loaded is Loaded. The tire is loaded by the the truck and then by the payload...by your theory, they should both change the rolling circumference. You can't use one load and ignore the other. Both are minuscule to circumference so I don't buy it and that's ok.
I just think you're theory is bogus.
I've never measured this, maybe I'll try it some day for fun. My opinion is that the inch is significant, but the 1/4 inch is splitting hairs. I agree with windsor when you load the initial curb weight of the vehicle, but then agree with you when the cargo is loaded in.
I never said anywhere I measured the tire OFF the truck. I take measurements for the Tirepaq while the tires are ON. This IS loaded with the truck weight and if I add a 1550lb load in the bed, by your theory, my speed will be off because I just loaded the tire more and changed it's circumference. I ain't buyin' it.
31" Ground to top of tire ( 15.5" radius)
14 3/4" Ground to center of rim (14.75" radius)
32" Front to back (16" radius)
31.9 Tire calculator for 275/55/20 (15.95" radius)
Sorry, I don't have 1400lbs to load my truck. I think your method works because it is easier to measure to the top of the tire than to find the center of the wheel. If your measuring your tires on the truck with a full cargo load, then your already applying 50% of windsor's theory.
That puts us 50% in agreement.
I measure mine on the truck and no cargo load at all, only the truck.
I think we've beat this horse enough.
Like I said before, let's all agree to disagree, even by your estimate of 50% (which incidentally, I think is closer to 30%) heehee!
.
Cheers
I think we've beat this horse enough.
Like I said before, let's all agree to disagree, even by your estimate of 50% (which incidentally, I think is closer to 30%) heehee!
.
Cheers


